若a,b,c为整数,且|a-b|+|c-b|=1,求|a-b|+|b-c|+|c-a|的值
若a,b,c为整数,且|a-b|+|c-b|=1,求|a-b|+|b-c|+|c-a|的值
若a,b,c为整数,且|a-b|+|c-b|=1,求|a-b|+|b-c|+|c-a|的值
若a,b,c为整数,且|a-b|+|c-b|=1,求|a-b|+|b-c|+|c-a|的值
根据|a-b|+|c-b|>=|c-a|,知道|c-a|=0或1,由于|c-a=0有C=a,这时2|b|=1与a,b,c为整数矛盾,所以
|c-a|=1,|a-b|+|b-c|+|c-a|=2
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收起
因为a,b,c为整数,所以|a-b|,|c-b|为大于等于0的整数,所以|a-b|=0,|c-b|=1或|a-b|=1,|c-b|=0,即a=b,|c-b|=|c-a|=|b-c|=1或b=c,|a-b|=|a-c|=|c-a|=1