(lg2)^2+lg20xlg5=谢谢了,
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(lg2)^2+lg20xlg5=谢谢了,
(lg2)^2+lg20xlg5=谢谢了,
(lg2)^2+lg20xlg5=谢谢了,
(lg2)^2+lg20*lg5=(lg2)^2+lg(2*10)*lg5 =(lg2)^2+(lg2+lg10)*lg5 =(lg2)^2+(lg2+1)*lg5 ==(lg2)^2+lg2*lg5+lg5 =lg2*(lg2+lg5)+lg5 =lg2*lg10+lg5=lg2+lg5=lg(2*5)=lg10=1
(lg2)^2+lg20xlg5=谢谢了,
(lg2)^2+lg20xlg5
lg2的平方+lg20xlg5
lg2^2+lg2*lg5+lg5=lg2(lg2+lg5)+lg5这个过程中,lg2的平方怎么没了?
(lg3分之2lg2+lg3分之3lg2)(lg2分之lg3+lg2分之2lg3)(2lg2分之lg3+3lg2分之lg3)(lg3分之lg2+2lg3分之lg2) 是这个上面那个大错了谢谢
lg2+lg2^2+lg2^3+……+lg2^10=
2lg2+lg2.lg2.2lg5+2lg5=?要写下了过程.
求值 :lg5²+lg2*lg50+(lg2)²答案写;2lg5+lg2*lg(5*10)+(lg2)²①=2lg5+lg2*lg5+lg2+(lg2)² ②=2lg5+lg2*(lg5+lg2)+lg2③ .第 ②步怎么得到的怎么就变成了lg2*lg5+lg2?
(lg2)^3+(lg5)^3+lg5*lg8=(lg2+lg5)[(lg2)^2-lg2*lg5+(lg5)^2]+lg5*lg2^3=1[(lg2)^2-lg2*lg5+(lg5)^2]+3lg5*lg2=(lg2)^2+(lg5)^2+2lg5*lg2=(lg2+lg5)^2=1网上看了看答案,可是第一步没有看懂.求得出第一步的过程,
(2lg5/lg2)*(2lg2/lg3)*(2lg3/lg5)求解,谢谢!我约分完后是lg5*lg2*lg3,可是别人说等于8,请教是哪里算错了?谢谢!
(lg2)^3+2lg2.lg5+(lg5)^3=题目写错了 = = 应该是 :(lg2)^3+3lg2.lg5+(lg5)^3
(lg2)^2+lg2*lg5+(lg5)^2=
(lg2^2+1)(lg2)^2+1=?
lg25+lg2·lg50+(lg2)^2=?
lg50+lg2*lg5+(lg2)^2=
lg25+lg2*lg50+(lg2)^2+1=?
lg^2 5+lg2*lg5+lg2=?
lg5*(1+lg2)+(lg2)^2=