2^(log4 (2-根号3))+3^(log9(2+根号3))=

log4^(1+根号2+根号3）+log4^（1+根号2-根号3）呵呵,摆脱了,呵呵, (log4(3)+log8(3))(log3(2)+log9(2))-log4(3)×log1/3(四次根号32) 2^log4(3) log4(3x-2) 2^log4^3=? 计算log9(根号2)*[log4(3)+log8(3)] (log2 5+log4 125)log3 2/ log根号3 5 2log4 (2-根号3)+3log9(2+根号3)错了 是2^(log4 (2-根号3))+3^(log9(2+根号3)) 计算：2^[log4(3) -2] 计算：2^log4(2--根号3）^2+2^log(2+根号3）^2 2^(log4 (2-根号3))+3^(log9(2+根号3))= 2log4 (2-根号3)²+3log9(2+根号3)² log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(2log4(3)*log9(2)+log2(4倍根号下64) log9(32)*log64(27)+log9(2)*log4(根27) log4^(根号5-根号3）+log4^(根号5+根号3）=? log4(根号5-根号3）+log4(根号5+根号3）等於? (log3,4+log9,4)log4,3—log2,2根号2 这怎么解答了 对数函数计算 log4 3·log9 2-log1/2 4次根号32 (log2(5）+log4（125））×log3（2）/log根号3（5）