(3a^2+2a-8)^2-(a^2-2a-8)^2=多少,
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/01 09:22:32
(3a^2+2a-8)^2-(a^2-2a-8)^2=多少,
(3a^2+2a-8)^2-(a^2-2a-8)^2=多少,
(3a^2+2a-8)^2-(a^2-2a-8)^2=多少,
用平方差公式:
(3a²+2a-8)²-(a²-2a-8)²
=[(a+2)(3a-4)]²-[(a+2)(a-4)]²
=(a+2)²[(3a-4)²-(a-4)²]
=(a+2)²[(3a-4)+(a-4)][(3a-4)-(a-4)]
=(a+2)²(4a-8)(2a)
=8a(a+2)²(a-2)
计算;(a^3)^4+a^10×a^2-a×a^2-a*a^3*a^8
计算(3a×a)+(2a×3a)+(3a×a)+[a×(a+2a+2a+2a+a)]
(a 1)(a 2)(a 3)(a
(a+2)(a+1)-a(a-3)
a-2a+3a-4a+5a-6a+7a-8a+9a-10a+11a.+99a-100a=
a-2a+3a-4a+5a-6a+...+99a-100a
化简; a-2a+3a-4a+5a-6a+``````-2006a+2007a.
(a+3a+5a+...+2009a)-(2a+4a+6a+...+2008a)=
(a+3a+5a+.+2009a)-(2a+4a+6a+.2008a)
计算(a+3a+5a+...+2009a)-(2a+4a+6a+...+2010a)
(a+3a+5a+...+2013a)-(2a+4a+6a+...+2012a)=
化简:a-2a+3a-4a+5a-6a+.+2010a+2011a.
计算(a+3a+5a+.+2003a)-(2a+4a+6a+...+2004a)
(a+3a+5a+.+2003a)-(2a+4a+6a+.+2004a)
(a+3a+5a...+2009a)-(2a+4a+6a+...+2010a)=?
5a^-〔a^-2a-2(a^-3a)]
a(a-1)(a-2)(a-3)(a-4)因式分解
2a*a+3a+2/a+1-a*a-a-5/a+2-3a*a-4a-5/a-2+2a*a-8a+5/a-3