3x/(x-3)²- x/3-x 1/a+1-2/1-a² b/3a+a/2b

3x/(x-3)²- x/3-x 1/a+1-2/1-a² b/3a+a/2b
3x/(x-3)²- x/3-x 1/a+1-2/1-a² b/3a+a/2b

3x/(x-3)²- x/3-x 1/a+1-2/1-a² b/3a+a/2b
3x/(x-3)²- x/3-x
=3x/(x-3)²+x/(x-3)
=(3x+x²-3x)/(x-3)²
=x²/(x-3)²
1/a+1-2/1-a²
=1/(1+a)-2/(1-a)(1+a)
=(1-a-2)/(1-a)(1+a)
=-(a+1)/(1-a)(1+a)
=-1/(1-a)
=1/(a-1)
b/3a+a/2b
=(2b²+3a²)/6ab

111111111

3x/(x-3)²- x/(3-x)
=3x/(x-3)²- x(3-x)/(x-3)²
=(3x-3x+x²)/(x-3)²
=x²/(x-3)²

1/(a+1)-2/(1-a²)
=(a-1)/(a²-1)+2/(a²-1)
=(a-1+2)/(a²-1)
=1/(a-1)

b/3a+a/2b (通分)
=(2b²+3a²)/6ab