若 |x^2-3xy-4y^2|+2√(x^2+4xy+4y^2-1)=0 求3x+6y的值
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若 |x^2-3xy-4y^2|+2√(x^2+4xy+4y^2-1)=0 求3x+6y的值
若 |x^2-3xy-4y^2|+2√(x^2+4xy+4y^2-1)=0 求3x+6y的值
若 |x^2-3xy-4y^2|+2√(x^2+4xy+4y^2-1)=0 求3x+6y的值
原方程等同于:
x^2-3xy-4y^2=0-----------(1)
x^2+4xy+4y^2-1=0---------(2)
(2)式整理得:(x+2y)^2=1.
x+2y=±1,代入方程(1),方程有解,所以:
3x+6y=±3
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