化简 1+sin(α-2π)*sin(π+α)-2cos^2(-α)
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/05 12:19:20
化简 1+sin(α-2π)*sin(π+α)-2cos^2(-α)
化简 1+sin(α-2π)*sin(π+α)-2cos^2(-α)
化简 1+sin(α-2π)*sin(π+α)-2cos^2(-α)
1+sin(α-2π)*sin(π+α)-2cos^2(-α)
=1+sina(-sina)-2cos^2(-α)
=-cos^2a=-(1+cos2a)/2
=1+sinαsinα-2cos^2(α)
=1+(1-cos2α)/2-(1+cos2α)
=0.5-1.5cos2α
化简sin(α+β)+sin(α-β)+2sinαsin(3π/2-β)=
化简1-sin[α-2π]sin[π+α]-2sin²[-α].
化简sin^2(α-π/6)+sin^2(α+π/6)-sin^2α
化简 1+sin(α-2π)*sin(π+α)-2cos^2(-α)
1+sin(α-2π)*sin(π+α)-2cos^2(-α) 化简
化简1+sin(α-2π)sin(π+α)-2cos^2(-α),
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化简:2cos²α-1/【2sin(π/4-α)sin²(π/4+α)】
化简1+sin(α-2π)sin(π+α)-2cos(-α)
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