lingo 程序sets:k/1..5/;z/1..8/:m;link(k,z):a,c,l,t,s;endsetsmin=a(i,j);@sum(z(j):a(4,j)*c(4,j))
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lingo 程序sets:k/1..5/;z/1..8/:m;link(k,z):a,c,l,t,s;endsetsmin=a(i,j);@sum(z(j):a(4,j)*c(4,j))
lingo 程序
sets:
k/1..5/;
z/1..8/:m;
link(k,z):a,c,l,t,s;
endsets
min=a(i,j);
@sum(z(j):a(4,j)*c(4,j))
lingo 程序sets:k/1..5/;z/1..8/:m;link(k,z):a,c,l,t,s;endsetsmin=a(i,j);@sum(z(j):a(4,j)*c(4,j))
sets:
k/1..5/;
z/1..8/:m;
link(k,z):a,c,l,s;
endsets
min=@sum(link:a);
@sum(z(j):a(4,j)*c(4,j))
lingo 程序sets:k/1..5/;z/1..8/:m;link(k,z):a,c,l,t,s;endsetsmin=a(i,j);@sum(z(j):a(4,j)*c(4,j))
关于LINGO程序lingo程序如下:sets:a/1..5/:x; endsets data:x=1,2,3,4,5;enddata 若知道a(i):x(i)=5,如何写出程序求出i的值
lingo利用for循环,有错误1 lingo有没有真为1这么一说2 @for(lianxi(i,j)| i #NE# j:(T(i)#EQ#1)*@floor((i+4)/5) #NE# (T(j)#EQ#1)*@floor((j+4)/5)); (j+4)/5))); 这句话哪有错误.整个程序是model:sets:jiaoshi/1..45/:dianliang,zuowei,K
这个lingo程序运行很长时间出不来结果model:sets:people/1..29/;group/1..5/;meeting/1..7/;links(people,group,meeting):x;links2(people,people)|&1#lt#&2:y;endsetsmax=@sum(links2:y);@for(people(i):@for(meeting(k):@sum(group(l):x(i,l,k))=1));@
这个lingo程序错在哪?我编了个lingo程序,测试的时候出错,感激不尽~以下是程序“MODEL:title 码流提取问题;SETS:job/1..5/;worker/1..16/;assign(job,worker):x,a,b;ENDSETSDATA:a=30.8667,32.7657,35.4304,37.781,40.3113,28.6755,
lingo中sets是什么?
lingo程序:model:sets:product/1..3/:a,b; row/1..5/:c,d,y; num/1..9/:x; endsets其中的product和num该怎么用?还有平时不是用的col么而不是num区别在哪?
lingo程序错在哪里?如何改?model:sets:yj/1..7/:z;yi/1..6/:;yk/1..5/:;sl1(yi,yj):x,d,s,k;sl2(yj,yk):a;sl3(yi,yk):b;endsetsdata:z=100 60 80 40 110 90 30;a=0.5 0.1 0.2 0.05 00.7 0.2 0 0.03 00 0 0.8 0 0.010 0.3 0 0.07 00.3 0 0 0.1 0.050.2 0.6 0 0
一段简单的LINGO线性规划程序lingo说解不出来啊,怎么回事?model:title:model2;sets:flag/1..2/:a;commercial/1..4/:m;!商品种类 已知;client/1..8/:c;!客户 已知;supply/1..5/:w;!货栈 已知;links(supply,client):n,t,x;!货栈和
Lingo@for循环和@if的语句 Lingo新手,不知道该怎么写程序,MODEL:SETS:city/A1..A4/:U;;links(city,city):distance,;quan/1..4/:A;demond/1..4/:D;link(quan,demond):c;ENDSETSDATA:distance=0,34,84,8,34,0,63,7,84,63,0,5,8,7,5,0;d=12,18,23,16;ENDD
lingo 不等于例如:xi不等于xj(i,j=1,2,3,4,5)其中i不等于j用lingo怎么编写程序.sets:ve/1..5/:c,x,b;endsets@for(ve(i)|i#ne#j:XXXXX);XXXXX 处怎么编写?
lingo中的错误提示在哪找?以下为所写程序,MODEL:sets:num_i/1..8/:x,k;num_p/9..22/:x,k;num_q/23..46/:x,k;num_j/1..3/:n,m,l;endsetsdata:n=43;59,39,41,27,28,34,21,24,24,20,25,21,23,21,18,31,23,22,59,18,25,35,29,30,42,28,42,45,49,50,64,52,63
lingo程序在如下程序中:MODEL:Traveling Salesman Problem for the cities ofAtlanta,Chicago,Cincinnati,Houston,LA ;SETS:CITY / 1..5/:U; U( I) = sequence no.of city;LINK( CITY,CITY):DIST,The distance matrix;X; X( I,J) = 1 if we use link I,J;ENDS
lingo程序哪儿错了?MODEL:sets:Quarters/1..4/:a,k,d,c,t,p;endsetsdata:k=25,35,30,10;d=10,15,25,20;c=1000,800,800,1000;t=13,12,12,10;p=7.04,7.04,7.04,7.04;enddatamin=@sum(Quarters:a*c*p*0.0001+(0.75t+1.08*p^3+15.71*p^2+76.80*p-116.55)*a+0.15*@sum(
lingo的数据拟合model:sets:xl/1..5/:n,y; endsets data:n=19,20,22,24,25; y=6,7,8,9,10; enddata @frmodel:sets:xl/1..5/:n,y;endsetsdata:n=19,20,22,24,25;y=6,7,8,9,10;enddata@free(a);@free(b);min=@sum((@log(y)*a-b-n)*(@log(y)*a-b-n));end这段程序
lingo 目标函数的代码编写目标函数为 程序为:MODEL:sets:Warehouse/1..4/:a; Customer/1..8/:b;prize/1..4/:p; qu/1..8/:q; Routes(Warehouse,Customer):c,x; endsets !here are the parameters; data: a=6,8,6,22; b=6,5,8,5,6,5,4,6; p=92,88,90,
我的这个lingo程序为什么解不出MODEL:sets:school/1..16/:c,alph,beta,x;zone/1..20/:children;student(school,zone):s,n;endsetsdata:alph=5 5 5 5 5 5 5 3.5 3.5 3.5 3.5 3.5 2 2 2 2;beta=0.15 0.15 0.15 0.15 0.15 0.15 0.15 0.1 0.1 0.1 0.1 0.1 0.05
最后解题时运行LINGO出现错误,error code108,我用的LINGO11.0,应该不是版本低吧?具体程序如下MODEL:SETS:SHOP/1..8/;FACTORY/1..3/;CANGKU/1..5/:KRL;WUZI/1..10/:TJ,KCF,ZXQL,Q,N;LINKS(SHOP,WUZI):XQL;LINKS1(FACTORY,WUZI):NCL,DJ,X;LIN