(+1)+(-3)+(+5)+(-7)+...+(2005)+(-2007)要具体算式..

1-3+5-7+... 7/3*[7/5-(7/3+5/1)]简便算法 1,3,5,7,9. 化简5／7：1／3 找出下面数字的规律 填空白处的数字7 7 2 5 7 5 3 5 7 4 7 3 7 4 7 5 5 3 7 5 7 3 7 7 7 5 5 3 5 7 5 4 4 7 5 7 7 5 7 5 4 7 5 3 7 __ 7 2 5 7 7 4 5 7 5 7 7 3 1 4 7 7 5 4 7 7 4 5 7 2 7 7 4 7 5 7 2 7 7 3 7 7 5 4 7 7 7 4 7 7 5 4 7 7 3 4 4 7 5 7 1*3+3*5+5*7+7*9+,+29*31 (1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简算(1+1/3+1/5+1/7)*(1/3+1/5+1/7+1/9)-(1+1/3+1/5+1/7+1/9)*(1/3+1/5+1/7) 简便计算 1/5+1/3*(3/5-3/7)简便计算 (3+5/7-2/3)×(1/5+1/7+1/13)-(1/5-1/7+1/13)×3+(1/5+1/7+1/13)×(2/3-7/5)有一个打错了(3+5/7-2/3)×(1/5+1/7+1/13)-(1/5-1/7+1/13)×3+(1/5+1/7+1/13)×(2/3-7/5) 1/1*3*5+1/3*5*7+1/5*7*9.+1/95*97*99 用Matlab用计算特征值和特征向量1 1/7 1/5 1/3 1/5 1/67 1 7/5 7/3 7/5 7/65 5/7 1 5/3 5/8 5/63 3/7 3/5 1 3/5 1/25 5/7 8/5 5/3 1 5/66 6/7 6/5 2 6/5 1 1/1*3+1/1*3*5+1/1*3*5*7+1/1*3*5*7*9-73/945 计算(-5)-(+3)+(-9)-(-7)+1/3 一元一次方程×-×-1/3=7-×+3/5 -3/7+3/2+1+-5 1+3+5+7+.+（2n-1) 1+1+3+5+7+9 [(-5)-(-1/3)+1/7]+(-105)=