化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1(1)化简f(x);(2)求f(π/12)的值
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化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1(1)化简f(x);(2)求f(π/12)的值
化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1
(1)化简f(x);
(2)求f(π/12)的值
化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1(1)化简f(x);(2)求f(π/12)的值
(1)f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1
=2cos(x/2)·sin(x/2)+2cos^2(x/2)-1
=sinx+cosx (倍角公式)
=√2sin(x+π/4)
(2)f(π/12)=√2sinπ/3=√6/2
f(x)=cos(2x)+2sin(x)化简
化简f(x)=2cos(x/2)·(sin(x/2)+cos(x/2))-1(1)化简f(x);(2)求f(π/12)的值
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