化简:1+sin(x-2π)cos(x-7π/2)-tan(π-x)tan(3π/2-x)-2cos^2(-x)
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/06 03:37:38
化简:1+sin(x-2π)cos(x-7π/2)-tan(π-x)tan(3π/2-x)-2cos^2(-x)
化简:1+sin(x-2π)cos(x-7π/2)-tan(π-x)tan(3π/2-x)-2cos^2(-x)
化简:1+sin(x-2π)cos(x-7π/2)-tan(π-x)tan(3π/2-x)-2cos^2(-x)
原式=1+(-sinx)*cos(x+π/2)-(-tanx)*tan(π/2-x)-2cos²x = 1+sin²x+tanx*cotx-2cos²x
= sin²x+2(1-cos²x)=3sin²x;
化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin...化简:[sin(2π-2)cos(π+x)tan(π-x)]/[cos(π-x)sin(3π-x)sin(-π-x)]
化简sin x/(1-cos x)√[(tan x-sin x)(tan)]化简sin x/(1-cos x)√[(tan x-sin x)/(tan x+sin x)]
化简(sin x+cos x-1)(sin x-cos x+1)/sin 2x
cos x/sin x+sin x/(1+cos x) 化简.
化简2sin(π-x)cosx+2cos²x
化简:[2cos³x-sin²(360°-x)+2sin(90°+x)+1]÷[2+2cos²(180°+x)+cos(-x)]
化简 1/2cos x-根号3/2sin x 根3sin x+cos x
化简[1-(sin^4x-sin^2cos^2x+cos^4x)/(sin^2)]+3sin^2x
化简1+sin x/cos x·sin2x/2cos²(π/4-x/2)
化简2sin^2[(π/4)+x]+根号3(sin^x-cos^x)-1
为什么sin(x+△x)-sinx= 2cos(x+x/x) sin △x/2
dy/dx的证明题目f(x)=cos x+sin x/cos x-sin x证明 f'(x)=2/1-sin 2x..
化简:1+sin(x-2π)cos(x-7π/2)-tan(π-x)tan(3π/2-x)-2cos^2(-x)
化简[1-(sin^4 x-sin^2 xcos^2 x+cos^4 x)]/(sin^2 x)+3sin^2 x
(1/2)已知向量m(sinωx,-√3cosωx),n=(sinωx,cos(ωx+π/2))(ω>0),若函数f(x)=m*n的最小...(1/2)已知向量m(sinωx,-√3cosωx),n=(sinωx,cos(ωx+π/2))(ω>0),若函数f(x)=m*n的最小正周期为
化简:y=cos^4 x+2 sinxcosx-sin^4 x
化简sin(x)cos(x)cos(2x)
化简sin(x)cos(x)cos(2x)