tan(π/8)+1/(tan(π/12))值,要过程

tan(π/12)-(1/tan(π/12)) 化简：tan(π/8)+1/tan(π/12) tan(π/8)+1/(tan(π/12))值,要过程 (1-tan^2π/12)/(tanπ/12)化简 计算 tanπ/12+1/tanπ/12 计算tanπ/12 / (1-tan^2π/12)= tan(π/12)+1/tan(π/12)=啥? tanπ/12-1/tanπ/12= (tan(5π/8)*tan(π/8))为什么等于-1 tanπ/8/(1-tan^2π/8) tanπ/8-1/tanπ/8是（tanπ/8）-〔1/（tanπ/8）〕。 三角函数算值题1-tan^2(π/8) /tan(π/8)=tan(15)/1-tan^2(15)= 化简：[tan(5/4)π+tan(5/12)π]/[1-tan(5/12)π] 化简：[tan（5π）/4+tan(5π)/12]/[1-tan(5π)/12] 求tan(π/8) tan(π/8)=? （tanπ/4+tanα)/(1-tanπ/4tanα)怎么解 利用正切函数单调性比较 函数值大小tan [(75/11)π]&tan [(-58/11)π]这样可不可以 下面算式有错吗tan[(75/11)π] = tan[(9/11)π] =tan[(1-2/11)π] = -tan 2/11 πtan [(-58/11)π] = tan [-(8/11)π] = -tan[(1-3/11)π] = tan 3/11 π