1.-10x^2z+25xyz-15y^2z2.x^2+(k+2)x+(k+1)

1.-10x^2z+25xyz-15y^2z2.x^2+(k+2)x+(k+1) √x+y-z+|3x-2y|+z²-10z+25=0求xyz的平方根快. 2x+3y+4z,xyz 因式分解 (x+y+z)^2+yz(y+z)+xyz 正数XYZ满足(X+Y)(X+Z)=2则XYZ(X+Y+Z)最大值 x+y=15 z+x=20 z+y=10 问xyz 各是多少 因式分解：25x y^2 z^2 (x+y-z)-30xyz(z-x-y)^2+5x y z^3 (z-x-y) 24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 24xy^2z^2(x+y+z)-32xyz(z-x-y)^2+8xyz^3(z-x-y) 3x^2y-{xyz-（2xyz-x^2z）-4x^2z+[3x^2y-(4xyz-5x^z-3xyz)]}化简 化简3X^2y-{xyz-(2xyz-9x^2z+4x^2z)+[3x^2y+(4xyz-5x^2z-3xyz)]}等于（ ）A 2xyz-2x^2z B 6x^2y-4xyz+2x^2zC 6x^2y+2xyz-10x^2z D 8xyz+10x^2z x+y+z+2=xyz,x,y,z.为正实数,证明：xyz(x-1)(y-1)(z-1) 已知根号（x+y-z）+|3x-2y|+z²-10z+25=0,求xyz的平方根 (x*x+2)(y*y+4)(z*z+8)=64xyz,求x,y,z Thanks!超急,十万火急的急!共有5题,在此分5题求解答!因式分解:-10 x^2 z + 25xyz - 15 y^2 z x^3+x^2y-x^z-xyz分解因式 已知x:y=2:3,y:z=9:10,且x+y+z=50,则xyz=? 先化简再求值3xyz+2(x^2y+y^2z-xyz)-xyz+2z^2x x=1 y= -1 z=2