若1/x-1/y=2,求(3x-2xy-3y)/(x-2y-y)的值

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若1/x-1/y=2,求(3x-2xy-3y)/(x-2y-y)的值
若1/x-1/y=2,求(3x-2xy-3y)/(x-2y-y)的值

若1/x-1/y=2,求(3x-2xy-3y)/(x-2y-y)的值
1/x-1/y=(y-x)/xy=2
y-x=2xy
所以x-y=-2xy
原式=[3(x-y)-2xy]/[(x-y)-2xy]
=[3(-2xy)-2xy]/[(-2xy)-2xy]
=-8xy/(-4xy)
=2

1/x-1/y=(y-x)/xy=2
即：y-x=2xy
(3x-2xy-3y)/(x-2xy-y)
=[-3(y-x)-2xy]/[-(y-x)-2xy]
=(-6xy-2xy)/(-2xy-2xy)
=(-8xy)/(-2xy)
=4大哥。。介个。。你好像算错了吧。。 -2xy-2xy应该是-4xy吧。。1/x-1/y=(y-x)/xy...

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1/x-1/y=(y-x)/xy=2
即：y-x=2xy
(3x-2xy-3y)/(x-2xy-y)
=[-3(y-x)-2xy]/[-(y-x)-2xy]
=(-6xy-2xy)/(-2xy-2xy)
=(-8xy)/(-2xy)
=4

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