cos(2x-π/3)+cos(2x+π/6)化简
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cos(2x-π/3)+cos(2x+π/6)化简
cos(2x-π/3)+cos(2x+π/6)化简
cos(2x-π/3)+cos(2x+π/6)化简
cos(2x-π/3)+cos(2x+π/6)
=2cos[(2x-π/3+2x+π/6)/2]*sin[(2x-π/3-2x-π/6)/2]
=-2cos(2x-π/12)*sinπ/4
=-√2cos(2x-π/12)
cos(2x-π/3)+cos(2x+π/6)化简
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