x+1=5(y+2),3(2x-5)-4(3y+4)=5解二元一次方程
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x+1=5(y+2),3(2x-5)-4(3y+4)=5解二元一次方程
x+1=5(y+2),3(2x-5)-4(3y+4)=5解二元一次方程
x+1=5(y+2),3(2x-5)-4(3y+4)=5解二元一次方程
由式1得x=5y+9代入式2得
3(2(5y+9)-5)-4(3y+4)=3(10y+13)-4(3y+4)=18y+23=5
所以y=-1
所以x=4
化简[(3x+4y)^2-(2x+y)(2x-y)+(-x+y)(5x-y)]除以-2y,其中x=-1,y=1
若2x-3y+4=0则x(x*x-1)+x(5-x*x)-6y+7
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)
{x+y=1 ,xy=-6{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
先化简再求值(x-y)(x-2y)+(x-2y)(x-3y)-2(x-3y)(x-4y) x=4 y=5
3x-2y=1 4x-5y
{(x+y)/2+(x-y)/3=1,(x+y)-5(x-y)=2.求x=?,y=?
化简求值{(x=2y)(5x-2y)-(3x+2y)(3x-2y)]/4x,其中x=2,y=-1
(x-y)/4+(x+y)/5=1/4 (x+y)/9-(x-y)/3=//2(x-y)/4+(x+y)/5=1/4(x+y)/9-(x-y)/3=//2
初二上学期方程题 4x+y=5 5x+4y=63x-2y=1 2x+3y=13x-2y=7 7x+5y=32x+3y=17 2x-y=-4x+5y=6 2x+y=23x-6y=4 3x+2y=52x+y=73x-4y=53x+y=1x-2y=-1x+y=42x+3y=92x-3y=74x+5y=3x+y=20004x+6y=90003x+5y=113x-2y=42x+3y=215x-2y=5x+y=54x+3y=182x+3y=16x+4y=132x+3y=40x
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
解下列方程组:{x(2x-3)=0,y=x²-1{(3x+4y-3)(3x+4y+3)=0,3x+2y=5{(x-y+2)(x+y)=0,x²+y²=8{(x+y)((x+y-1)=0,(x-y)(x-y-1)=0
4x-3y=5 x^2+y^2=1 求x,y
{(x+y)/2=(3x+4y)/5,(x+y)/2=1,
3x+4y-5=0 x^2+y^2=1求x.y