(1/2)A quickly breakfast 和what fine weather中的 breakfast和weather 同是不可数名词但
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(1/2)A quickly breakfast 和what fine weather中的 breakfast和weather 同是不可数名词但
(1/2)A quickly breakfast 和what fine weather中的 breakfast和weather 同是不可数名词但
(1/2)A quickly breakfast 和what fine weather中的 breakfast和weather 同是不可数名词但
breakfast在这里是可数名词,a quick breakfast 是“一次吃得很快的早餐”;weather 是不可数名词,故前面不能用a.
三餐前出现修饰词就要加冠词 have a quick breakfast=== have breakfast quickly
你确定没抄错的话breakfast不是名词。理由:quickly 是副词,副词在句中一般修饰形容词和动词,放在被修饰词的后面,如:run quickly等。
这是固定语法
Break up so quickly,how to keep .
break a
break a
break a
break a
c 语言改错#include stdio.hvoid main(){int a,b,year,day,month;scanf(%d%d%d,&year,&month,&day);switch(month){case 1:month=0;break;case 2:month=31;break;case 3:month=59;break;case 4:month=90;break;case 5:month=120;break;case 6:month=151;break;ca
the house is ( )fire ;call( )help quickly,or break the glass to sound the alarm.A.on,for B.at,for C.in,to D.on,to
若有定义语句int a,b; double x;下列选项中没有错误的是A)switch ( x%2){case 0 :a++;break;case 1 :b++;break;default :a++;b++;}B)switch ( (int)x%2.0){case 0 :a++;break;case 1 :b++;break;default :a++;b++;}C)switch ( (int)x%2){c
quickly!已知a
A little less quickly
#include main() { int x=1,y=0,a=0,b=0; switch(x) { case 1: switch(y) { case 0: a++; break#include main() { int x=1,y=0,a=0,b=0; switch(x) { case 1: switch(y) { case 0: a++; break; case 1: b++; break; } case 2: a++; b++; break; }printf(“%d,%d
Take A Break
TAKE A BREAK
what about a break
take a break
请问taking a break
to have a break
Have a break?