1/2x3+1/3x4+1/4x5+1/5x6+1/6x7简便计算,做得好的有悬赏

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/07 16:47:05

1/2x3+1/3x4+1/4x5+1/5x6+1/6x7简便计算,做得好的有悬赏
1/2x3+1/3x4+1/4x5+1/5x6+1/6x7简便计算,做得好的有悬赏

1/2x3+1/3x4+1/4x5+1/5x6+1/6x7简便计算,做得好的有悬赏
1/3x2+1/3x4+1/4x5+1/5x6+1/6x7
=(1/2-1/3)+(1/3-1/4)+(1/4-1/5)+(1/5-1/6)+(1/6-1/7)
=1/2-1/7 (上式前括后一项与后括号前一项抵消)
=5/14

1/1X2+1/2X3+1/3X4+1/4X5+1/5X6+1/6X7
=1-1/2+1/2-1/3+1/3-1/4+....+1/6-1/7
=1-1/7
=6/7
望采纳
谢谢!

1x2+2x3+3x4+4x5+.+15x16 x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x1,x2,x3,x4,x5 求非齐次线性方程组的通解x1+3x2+5x3-4x4=1x1+3x2+2x3-2x4+x5=-1x1-2x2+x3-x4-x5=3x1+2x2+x3-x4-x5=3 解一道方程组x1+x2+x3=5,x2+x3+x4=1,x3+x4+x5=-5,x4+x5+x1=-3,x5+x1+x2=2 若x1,x2,x3,x4,x5满足方程组:x1-x2+x3=1 x2-x3+x4=2 x3-x4+x5=3 x4-x5+x1=4 x5-x1+x2=5 求x2,x3,x4的少打了个字,是求x2,x3,x4的值 1/1x3+1/2x4+1/3x5+ x1-x2+x3=1x2-x3+x4=21若x1,x2,x3,x4,x5满足方程组 x3-x4+x5=3x4-x5+x1=4x5-x1+x2=5求x2 x3 x4的值2已知 x1+x4+x6+x7=39 x2+x4+x5+x7=49 x3+x5+x6+x7=41 x4+x7=13 x5+x7=14 x6+x7=9 x1+x2+x3+x4+x5+x6+x7=9求x7的值若x1,x2,x3,x4,x5满足方程组 x1-x 求非其次线性方程组 {x1+2x2+x3+x4+x5=1x1+2x2+x3+x4+x5=12x1+4x2+3x3+x4+x5=2-x1-2x2+x3+3x4-x5=5 2x3+4x4-2x5=6 的一般解 求线性方程组的全部解,并用对应导出组的基础解系表示X1+3X2+5X3-4X4=1 X1+3X2+2X3-2X4+X5=-1 X1-2X2+X3-X4-X5=3 X1-4X2+X3+X4-X5=3 X1+2X2+X3-X4+X5=-1 求解线性方程组 x1-2x2+3x3-x4-x5=2 x1+x2-x3+x4-2x5=1 2x1-求解线性方程组x1-2x2+3x3-x4-x5=2x1+x2-x3+x4-2x5=12x1-x2+x3-2x5=22x1+2x2-5x3+2x4-x5=5 简算:1/1x2+1/2x3+1/3x4+1/4x5 1/1x2 + 1/2x3 + 1/3x4 + 1/4x5 已知数据x1,x2,x3,x4,x5的平均数是20,那么另一组数据x1,x2+1,x3+2,X4+3,X5+4的平均数 x5-x4+x3-x2+x-1因式分解 X5-X4+X3+X2+X+1因式分解 求下列非齐次线性方程组的通解(1){x1+x2+x3+x4+x5=2;x1+2x2-4x5=-2;x1+2x3+2x4+6x5=6;4x1+5x2+3x3+3x4-x5=4}(2){x1-x2+5x3-x4=1;x1+x2-2x3+3x4=1;2x1+3x3+2x4=2;2x1+4x2-11x3+10x4=2}(3){x1+x2+x3+x4+x5=1;3x1+2x2+x3+x4-3x5=0 简算.1/1X2+1/2X3+1/3X4+1/4X5+.+1/199X200, 1x2/1+2x3/1+3x4/1+4x5/1+…+39x40/1 求1/(1x2)+1/(2x3)+1/(3x4)+1/(4x5)+.+1/(2005x2006)