f(x+y)=f(x)+f(y)-1,f(-1/2)=0.求单调性当x> -1/2时。f(x)>0
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f(x+y)=f(x)+f(y)-1,f(-1/2)=0.求单调性当x> -1/2时。f(x)>0
f(x+y)=f(x)+f(y)-1,f(-1/2)=0.求单调性
当x> -1/2时。f(x)>0
f(x+y)=f(x)+f(y)-1,f(-1/2)=0.求单调性当x> -1/2时。f(x)>0
f(-1/2)=f(-1/2+0)
=f(-1/2)+f(0)-1
=f(0)-1=0
f(0)=1
f(-1)=f(-1/2)+f(-1/2)-1=-1
f(-2)=f(-1)+f(-1)-1=-1-1-1=-3
所以函数在(-∞,0]内单调递减
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