xy/3x+2y=1/8 xy/2x+3y=1/7这是一个方程组,
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xy/3x+2y=1/8 xy/2x+3y=1/7这是一个方程组,
xy/3x+2y=1/8 xy/2x+3y=1/7
这是一个方程组,
xy/3x+2y=1/8 xy/2x+3y=1/7这是一个方程组,
设X=kY.
kY^2/(3k+2)Y=1/8
kY^2/((2k+3)Y=1/7
由上式得:3k+2=8kY,2k+3=7kY
所以2/(8Y-3)=3/(7Y-2)
所以Y=1/2,X=1
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