若|x+y-5|+(x-y+1)²=0,则x²-y²=

若|x+y-5|+(x-y+1)²=0,则x²-y²=
若|x+y-5|+(x-y+1)²=0,则x²-y²=

若|x+y-5|+(x-y+1)²=0,则x²-y²=
x+y-5=0;
x-y+1=0;
2x-4=0;
x=2;
y=3;
∴x²-y²=4-9=-5;
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∵|x+y-5|≥0，(x-y+1)²≥0
又∵|x+y-5|+(x-y+1)²=0
∴|x+y-5|=0，(x-y+1)²=0
即{x+y-5=0
{x-y+1=0
解二元一次方程组得（过程省略）
{x=2
{y=3
x²-y²=2²-3²=-5