已知x^2+y^2-2x+2y+2=0,求代数式x^2003+y^2004的值
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已知x^2+y^2-2x+2y+2=0,求代数式x^2003+y^2004的值
已知x^2+y^2-2x+2y+2=0,求代数式x^2003+y^2004的值
已知x^2+y^2-2x+2y+2=0,求代数式x^2003+y^2004的值
x^2+y^2-2x+2y+2=0
x²-2x+1+y²+2y+1=0
∴(x-1)²+(y+1)²=0
∴x-1=0
y+1=0
∴x=1
y=-1
∴x^2003+y^2004=1+1=2
x=1,y=-1,所以x^2003+y^2004为2
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