英语翻译In a computer program,separate loops with distinct indices produce M and Noperations,respectively.If these reside internally in a loop with an independent indexproducing P operations,find the total number of operations represented by the

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英语翻译In a computer program,separate loops with distinct indices produce M and Noperations,respectively.If these reside internally in a loop with an independent indexproducing P operations,find the total number of operations represented by the
英语翻译
In a computer program,separate loops with distinct indices produce M and N
operations,respectively.If these reside internally in a loop with an independent index
producing P operations,find the total number of operations represented by the three loops.

英语翻译In a computer program,separate loops with distinct indices produce M and Noperations,respectively.If these reside internally in a loop with an independent indexproducing P operations,find the total number of operations represented by the
问题：
在一个计算机程序中,两个各自有独立指数的回圈分别产生 M 个和 N 个运算.若这些回圈都是位於另一个有独立指数,并会产生 P 个运算的回圈之内,请找出这三个回圈合共所代表的运算总数.
我的建议答案：
外回圈每运算一次,在它里面的两个回圈便会分别产生 M 个和 N 个运算,亦即会产生 (M + N) 个运算.所以,当外回圈运算 P 次之後,两个内回圈便会合共产生 P * (M + N) 个运算.再加上外回圈自己的 P 个运算,三个回圈合共代表的运算总数便等於：
P * (M + N) ＋ P = P * (M + N + 1)
所以答案应该是：P * (M + N + 1)

在计算机程序中,单独的循环与不同的指数分别产生M和Noperations。如果这些驻留在内部的一个循环有独立的indexproducing P操作,发现由三环路表示操作的总数。

在计算机程序中,单独的循环与不同的指数产生M和N
操作,分别。如果这些驻留在内部在一个循环的一个独立的指数
生产P操作,找到总数量的操作表示为三个循环。

在计算机程序中，用不同的指标生产和noperations单独的回路，分别。如果这些居住在内部有独立的indexproducing P操作回路，发现由三环路表示操作的总数。

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a computer program, separate loops with distinct indices produce M and Noperations, respectively.
一个计算机程序，用不同的指标生产和noperations单独的回路，分别。
If these reside internally in a loop with an independent indexproducing P operations, find the total number of operations represented by the three loops
如果这些居住在内部有独立的indexproducing P操作回路，发现由三环路表示操作的总数

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：
在计算机程序中，这两个各自独立的指数环分别生成M和N的运算。如果这些环路内循环的另一个独立的指数，P OP，请确定三环路，共占总数的业务。

我的建议答案：
每个操作循环时间，两个回路，它会生成M和N的运算，这将产生（M + N）的计算。所以，当外循环算子P后，两个内部循环将达到生产P *（M + N）运算。再加上三环路外循环P OP，合共占总数...

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