分解因式(x²+y²)³+(z²-x²)³-(y²+z²)³=
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分解因式(x²+y²)³+(z²-x²)³-(y²+z²)³=
分解因式(x²+y²)³+(z²-x²)³-(y²+z²)³=
分解因式(x²+y²)³+(z²-x²)³-(y²+z²)³=
(x²+y²)³+(z²-x²)³-(y²+z²)³
= [(x²+y²)+(z²-x²)][(x²+y²)²+(z²-x²)²-(x²+y²)(z²-x²)]-(y²+z²)³
= (y²+z²)[(x²+y²)²+(z²-x²)²-(x²+y²)(z²-x²)]-(y²+z²)³
= (y²+z²)[(x²+y²)²+(z²-x²)²-(x²+y²)(z²-x²)-(y²+z²)²]
= (y²+z²)[(x²+y²-y²-z²)(x²+y²+y²+z²)+(z²-x²)(z²-x²-x²-y²)]
=(y²+z²)[(x²-z²)(x²+2y²+z²)+(z²-x²)(z²-2x²-y²)]
=(y²+z²)[(x²-z²)(x²+2y²+z²-z²+2x²+y²]
=3(y²+z²)(x²-z²)(x²+y²)