(1/3+1/5)×15=?(1/9+1/3)×27=?(1/6+1/4)×36=?89×7/88=?要简便运算,

来源：学生作业帮助网 编辑：作业帮 时间：2024/11/08 20:39:37

(1/3+1/5)×15=?(1/9+1/3)×27=?(1/6+1/4)×36=?89×7/88=?要简便运算,
(1/3+1/5)×15=?(1/9+1/3)×27=?(1/6+1/4)×36=?89×7/88=?要简便运算,

(1/3+1/5)×15=?(1/9+1/3)×27=?(1/6+1/4)×36=?89×7/88=?要简便运算,
(1/3+1/5)×15
=1/3×15+1/5×15
=5+3
=8
(1/9+1/3)×27
=1/9×27+1/3×27
=3+9
=12
(1/6+1/4)×36
=1/6×36+1/4×36
=6+9
=15
89×7/88
=(88+1)×7/88
=7+7/88
=7又7/88

(1/3+1/5)×15=5+3=8
(1/9+1/3)×27=3+9=12
(1/6+1/4)×36==6+9=15
89×7/88=(88+1)×7/88=7+×7/88=7又×7/88

直接去括号，如第一道（1/3+1/5)x15=(1/3)x15+(1/5)x15=5+3=8,同理，9+3=12,6+9=15

(1/3+1/5)×15=1/3×15+ 1/5×15=5+3=8
(1/9+1/3)×27=1/9×27+1/3×27=3+9=12
(1/6+1/4)×36=1/6×36+1/4×36=6+9=15
89×7/88=(88+1)×7/88=88×7/88+1×7/88=7+7/88=7又 7/88

1/3+1/5+1/7+1/9+1/11+1/13+1/15= 2/15*( )=( )*3/4=15*( )=( )*9=1又1/5*( )=1 3*(1/9+1/15)+x*(1/12+1/15)=5/6 (1/9+1/15)*3+(1/12+1/15)X=5/6 (1-1/3)×(1-1/5)×(1-1/7)×(1-1/9)×(1-1/11))×(1-1/13)×(1-1/15)= 1+1/15+3+1/35+5+1/63+7+1/99+9+1/143+11+1/195=? 1/15:1/5=1/x:1/3 1+3+5+7+9+11+13+15= 谁会用MATLAB计算 权向量矩阵是A=[1,1/2,3,1,6,8,9,1/2 2,1,5,2,10,15,16,1 1/3,1/5,1,1/3,3,2,3,1/5 1,1/2,3,1,5,7,8,1/2 1/6,1/10,1/3,1/5,1,1,1,1/11 1/8,1/15,1/2,1/7,1,1,1,1/15 1/9,1/16,1/3,1/8,1,4/5,1,1/17 2,1,5,2,11,15,17,1];求权向量就是 1/1*3+1/3*5+1/5*7+1/7*9+1/9*11+1/11*13+1/13*15+1/15*17+1/17*19+1/19*21= 1/5 (X+15)=1/2减1/3(X-9) 解方程：1/3*15x=15*9、1/3*9=15*9 简算1*3/1+3*5/1+5*7/1+7*9/1+9*11/1+11*13/1+13*15/1+15*17/1+17*19/1 1,3,5,7,9,11,15 1-1/3-1/4=?,1/7×7÷1/7×7=?,1-5÷9=?,3/4×5/6×8/15=? (1/2+1/4+1/6+1/8)-(1/3+1/6+1/9+1/12)+(1/4+1/8+1/12+1/16)-(1/5+1/10+1/15+1/20)= 1-1/2+1/3-1/4+1/5-1/6+…+1/15=23*[1/( )+1/( )+1/( )+1/( )] 1/3,1/5,1/9,1/15,1/23,（）,（）./3