help me ,please~已知:二次函数y=-x²+bx+c与X轴交于点M(-1,0),N(n,0)两点,与Y轴交于点H.问:(1)若∠HMO=45°时,求函数解析式;(2)求△MNH的面积.
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help me ,please~已知:二次函数y=-x²+bx+c与X轴交于点M(-1,0),N(n,0)两点,与Y轴交于点H.问:(1)若∠HMO=45°时,求函数解析式;(2)求△MNH的面积.
help me ,please~
已知:二次函数y=-x²+bx+c与X轴交于点M(-1,0),N(n,0)两点,与Y轴交于点H.
问:(1)若∠HMO=45°时,求函数解析式;
(2)求△MNH的面积.
help me ,please~已知:二次函数y=-x²+bx+c与X轴交于点M(-1,0),N(n,0)两点,与Y轴交于点H.问:(1)若∠HMO=45°时,求函数解析式;(2)求△MNH的面积.
1.∠HMO=45°,M(-1,0)=》H(0.1)
讲H与M的坐标代入y=-x2+bx+c==》C=1,b=0
因此函数解析式为:y=-x2+1
2.因为N(n.0)由1,代入,得0=-(n)^2+1=》n=+/-1
以为N在X的右半轴,因此n=1
所以S△MNH=MN的绝对值XOH/2=2X1/2=1
因为∠HMO=45°所以OH=OM故H(1,0),所以中C=1 M(-1,0)带入y=-x²+bx+1故b=o故y=-x²+1.
S△MNH=c(n+1)/2
1)∠HMO=45°时则H(0,1)即c=1,将(-1,0)代入y=-x²+bx+c,得b=0
故y=-x²+1.
2)S△MNH=c(n+1)/2
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