(3x^2-2x+1)^2-(3x^2-2x-5)^25/2(x-2y)^2n*[-(2y-x)]^n+1*(2x-4y)^30.4^4*(-5/8)^6➗(-0.125)^3➗(25/16)^2解方程(3x+1)(2u-1)=6(x+2)(y-1)(X-2)(y-4)=(x-1)(y-1)

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