已知x=-2010,y=2009,z=-2008,求x^2+y^2 +z^2+xy+yz-xz的值
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/08 09:36:35
已知x=-2010,y=2009,z=-2008,求x^2+y^2 +z^2+xy+yz-xz的值
已知x=-2010,y=2009,z=-2008,求x^2+y^2 +z^2+xy+yz-xz的值
已知x=-2010,y=2009,z=-2008,求x^2+y^2 +z^2+xy+yz-xz的值
x²+y²+z²+xy+yz-xz
=(2x²+2y²+2z²+2xy+2yz-2xz)÷2
=[(x+y)²+(y+z)²+(x-z)²]÷2
=[(-2010+2009)²+(2009-2008)²+(-2010+2008)²]÷2
=(1+1+4)÷2
=3
=(2x^2+2y^2 +2z^2+2xy+2yz-2xz)/2
=[(x+y)²+(y+z)²+(x-z)²]/2
=﹙1+1+4﹚/2
=3
原式=(X+Y)^2+(Y+Z)^2-2XY-2YZ-Y^2+XY+YZ-XZ=(X+Y)^2+(Y+Z)^2-XY-Y^2-YZ-XZ=(X+Y)^2+ (Y+Z)^2-Y(X+Y)-Z(X+Y)=(X+Y)^2+(Y+Z)^2-(X+Y)(Y+Z)然后把数字带入即可
已知 x/(y+z)+y/(z+x)+z/(x+y)=1求 (x*x)/(y+z)+(y*y)/(x+z)+(z*z)/(x+y)=?
已知(x+y)(x+z)=x,(y+z)(y+x)=2y,(z+x)(z+y)=3z,求x,y,z
已知 (x+y-z)/z=(x-y+z)/y=(y+z-x)/x,且xyz≠0,求代数式 ((x+y)(y+z)(x+z))/xyz
分式加减法:已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z
已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z的步骤
已知x+y/z=x+z/y=y+z/x(x+y+z≠0),求x+y-z/x+y+z的步骤
已知:x^2/(z+y)+y^2/(x+z)+z^2/(x+y)=0,求x/(z+y)+y/(x+z)+z/(x+y)的值.
已知X+Y+Z=0,求(X+Y)(Y+Z)(X+Z)+XYZ的值.
已知x+y+z=0,求(x+y)(y+z)(z+x)+xyz的值
已知x+y+z=0,求(x+y)(y+z)(x+z)+xyz的值
已知x+y+z=0求证x*x*x+y*y*y+z*z*z=3xyz
已知(y+z)/x=(z+x)/y=(x+y)/z,则(y+z)/x的值是多少
已知{x+2y=2009, y+2z=2010, z+2x=2011,则x+y+z=_______.
已知x+y=2009,y+2z=2010,z+2x=2011,则x+y+z=多少
已知x/(y+z+u)=y/(z+u+x)=z/(u+x+y)=u/(x+y+z)求(x+y)/(z+u)+(y+z)/(x+u)+(z+u)/(x+y)+(u+x)/(y+z)
已知:(x+y-z)/z=(x-y+z)/y+(y+z-x)/x,且xyz≠0,求代数式[(x+y)(y+z)(x+z)]/xyz的值已知:(x+y-z)/z=(x-y+z)/y=(y+z-x)/x,且xyz≠0,求代数式[(x+y)(y+z)(x+z)]/xyz的值 题目中写错个等号,汗...
已知x-y/x+y=y+z/2(y-z)=z+x/3(z-x),求证8x+9y+5z=0THX..
已知实数x y z满足x/(x+1)=y/(y+2)=z/(z+3)=(x+y+z)/3,求x+y+z的值