x→0时,若x-[sin(x^3)]^1/3与Ax^k是等价无穷小,求A和k
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/08 20:28:13
x→0时,若x-[sin(x^3)]^1/3与Ax^k是等价无穷小,求A和k
x→0时,若x-[sin(x^3)]^1/3与Ax^k是等价无穷小,求A和k
x→0时,若x-[sin(x^3)]^1/3与Ax^k是等价无穷小,求A和k
sin(x^3) = x^3 - x^9/6 + O(x^11)
由[sin(x^3)]^1/3 (x^3)^1/3=x
可设 [sin(x^3)]^1/3 = x +ax^b+o(x^b)
则[x +ax^b+o(x^b)]^3=x^3+3ax^(2+b)+o(x^(b+2))
有 3a=-1/6,2+b=9 即a=-1/18,b=7
∴ x-[sin(x^3)]^1/3 x - ( x - x^7/18x+o(x^7)) = x^7/18
求极限 ((sin(x^3+x^2-x)+sin x) /x x→0 已知lim sinx/x=1
为什么当x→0时极限sin(x*sin(1/x))/x*sin(1/x)不存在
lim(x→0)×(x-sin²3x)/x
lim x->0 (sin x-tan x)/sin (x^3)
若SIN X*COS X =1/3,已知0
(sin 1/x) /x
lim (x→0)x sin 1/x=
数学达人帮助求极限!当x->0时sin(x)=x+o(x)x*cos(x)=x-x^3/2!+o(x^3)sin(x)^3=x^3+o(x)lim(sin(x)-x*cos(x)/sin(x)^3=1/2请问错在哪里?谢谢!
求(sin(x∧2sin(1/x)))/x当x→0时的极限
sin(sinx)/x,x 趋于0的极限sin(sin(x))/x=[sin(sin(x))/sin(x)]*sin(x)/x=1*1=1sin(sin(x))/sin(x)这一部我不明白阿
当x趋于0时:lim (tan x - sin x )/x^3 lim [(a^x+b^x+c^x)/3]^(1/x) ( a,b,c > 0 )
当x趋于0时,x^3-sin(x^2)与sin(x^2)是等价无穷小吗?求当x趋于0时 极限lim x^3-sin(x^2) / x^2= 老师说 x^3-sin(x^2)与x^2为等价无穷小可是我算 lim x^3-sin(x^2)/ sin(x^2)= x^3/x^2 - 1=x-1 =-1-1 也是等价无穷小
3道求极限的题目1.sin 2x/sin 5x (x→0)2.(sin x - sin a)/(x - a) (x→a)3.sin ωx/x (x→0)
求x→0时lim[e^x-e^(-x)-2x]/sin^3x的极限要过程,谢谢
lim(x→0)[tan(2x+x^3)/sin(x-x^2)]
lim(x->0) 1-x^2-e^(-x^2)/x*sin^(3)2x
lim(x ->0)sin x /x ^3+3x
lim (x->0) sin(3x)+4x/xsec(x)