已知4x-3y-6z=0,x+2y-7z=0(xyz不等于0),求2x+3y+6z除以x+5y+7z的值

已知4x-3y-6z=0,x+2y-7z=0(xyz不等于0),求2x+3y+6z除以x+5y+7z的值
已知4x-3y-6z=0,x+2y-7z=0(xyz不等于0),求2x+3y+6z除以x+5y+7z的值

已知4x-3y-6z=0,x+2y-7z=0(xyz不等于0),求2x+3y+6z除以x+5y+7z的值
将4x-3y-6z=0,x+2y-7z=0移项转化成以下方程组：
4x-3y=6z,
x+2y=7z
解得：x=3z,y=2z
(2x+3y+6z)/(x+5y+7z)=(6z+6z+6z)/(3z+10z+7z)=9/10