已知x^2+y^2=7,xy=-1,求代数式:5x^2-(3xy+4y^2)-(11xy-2y^2)-7x^2
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/09 02:00:58
已知x^2+y^2=7,xy=-1,求代数式:5x^2-(3xy+4y^2)-(11xy-2y^2)-7x^2
已知x^2+y^2=7,xy=-1,求代数式:5x^2-(3xy+4y^2)-(11xy-2y^2)-7x^2
已知x^2+y^2=7,xy=-1,求代数式:5x^2-(3xy+4y^2)-(11xy-2y^2)-7x^2
5x^2-(3xy+4y^2)-(11xy-2y^2)-7x^2
=5x^2-3xy-4y^2-11xy+2y^2-7x^2
=-2x^2-2y^2-14xy
=-2(x^2+y^2)-14*xy
=-2*7-14*(-1)
=-14+14
=0
=5x²-3xy-4y²-11xy=2y²-7x²
=-2x²-14xy-2y²
=-2(x²+7xy+y²)
=-2(x²+y²+7xy)
=-2(7-7)
=-2乘0
=0
=5x^2-3xy-4y^2-11xy+2y^2-7x^2
=-2x^2-14xy-2y^2
=-2(x^2+y^2)-14xy
=-2*7-14*(-1)
=0
已知1/x-1/y=5,求分式y+xy-x/2x+7xy-2y的值.
已知1/x-1/y=5 求分式-x+xy+y/2x+7xy-2y
已知1/X-1/y=5,求分式(y+xy-x)/(2x+7xy-2y)的值
已知X+y=6,xy=7 求x^2y+xy^2=已知X+y=6,xy=7 x^2y+xy^2
已知3/(x-y)=1/xy 求(-x-2xy+y)/ (2x+3xy-2y)
已知xy-x-y=11,求(xy-1)^2+(x+y-2)(x+y-2xy)的值.
已知1/x+1/y=3,求分式(3x-3xy+3y)/(x+xy+y)的值我知道第一步是两边都乘以xy得x+y=3xy,然后怎么代进去,求回答!
已知1/x-1/y=2,求3x+7xy-3y/2x-3xy-2y答案是1/x-1/y=2(y-x)/xy=2 得:x-y=-2xy(3x+7xy-3y)/(2x-3xy-2y)=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy)=xy/(-7xy)=-1/7 谁能帮我解释一下=[3(x-y)+7xy]/[2(x-y)-3xy]=(-6xy+7xy)/(-4xy-3xy) 是怎
已知,x-y=2,xy=7 求x^2 y-xy^2
已知xy^2=-2求xy(2x^3y^7+5x^2y
已知x+y=0,xy=-7,求x^2y+xy^2
已知x+y=2,xy=7求x²y+xy²的值
已知整数x和y,满足x^+xy-2y^=7,求xy的值
已知x+y=-1,xy=-2,求代数式-5(x+y)+(x-y)+x(xy+y)的值
.已知:x-y=1,xy=-2.求:(-2xy+2 x+3y)-(3xy+2y-2x)-(x+4y+xy)的值
已知x y=1,xy=-3,求2xy-4x 4(y-2(xy-x))
已知x-xy=8,xy-y=-9,求x+y-2xy的值
已知x=3y,试求(x-y)^2+2xy-y^2/x^2+7xy+y^2