lim[n/(n^2+1^2)+n/(n2+2^2)+···n/(n^2+n^2)] n->无穷大
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 21:44:41
lim[n/(n^2+1^2)+n/(n2+2^2)+···n/(n^2+n^2)] n->无穷大
lim[n/(n^2+1^2)+n/(n2+2^2)+···n/(n^2+n^2)] n->无穷大
lim[n/(n^2+1^2)+n/(n2+2^2)+···n/(n^2+n^2)] n->无穷大
n/(n^2+i^2) = (1/n)/(1+(i/n)^2)
所以原式 = ∫(0,1) 1/(1+x^2)dx = arctanx|(0,1)=π/4
lim(n+3)(4-n)/(n-1)(3-2n)
lim[(n+3)/(n+1))]^(n-2) 【n无穷大】
lim(2^n+3^n)^1
(n趋向无穷)
lim(n^3+n)/(n^4-3n^2+1)
lim (n!+(n-1)!+(n-2)!+(N-3)!+⋯..+2!+1)/n!其中n→∞
lim(1-1/n)^(n^2)=?
lim(1-1/n^2)^n=?
lim(n→∞) ((2n!/n!*n)^1/n的极限用定积分求是lim(n→∞) 1/n(2n!/n!)^1/n 不好意思
Lim n-无穷大 n/(n^2+1^2)+n/(n^2+2^2)+.n/(n^2+n^2)
高数题:n趋近于0,lim{1/(n^2+n+1)+2/(n^2+n+2)+3/(n^2+n+3)+.+n/(n^2+n+n)}=?
lim[n/(n*n+1*1)+n/(n*n+2*2)+...+n/(n*n+n*n)],当x趋向无穷大时,怎么求极限,
lim根号n^2+n+1/3n-2
lim根号n^2+n+1/3n-2=?
lim (2n-1)/(2^n)=?n=>无穷大
lim n->无穷大(2^n-1)/(3^n+1)
lim (1+1/2n)^n n趋向于无穷大
lim n->∞{2/((1+ 1/n )^n)}=?
lim(1+1/(n+2))^n其中n趋近无穷