()/()()+()/()()+()/()()=1 括号里填1-9的数字,使等式成立,并且不能重复分母是几十几,看清楚吧

来源:学生作业帮助网 编辑:作业帮 时间:2024/11/05 21:35:41

()/()()+()/()()+()/()()=1 括号里填1-9的数字,使等式成立,并且不能重复分母是几十几,看清楚吧
()/()()+()/()()+()/()()=1
括号里填1-9的数字,使等式成立,并且不能重复
分母是几十几,看清楚吧

()/()()+()/()()+()/()()=1 括号里填1-9的数字,使等式成立,并且不能重复分母是几十几,看清楚吧
一共有48种做法:
1/(3*6)+7/(2*4)+5/(8*9)= 1
1/(3*6)+7/(4*2)+5/(8*9)= 1
1/(6*3)+7/(2*4)+5/(8*9)= 1
1/(6*3)+7/(4*2)+5/(8*9)= 1
7/(2*4)+1/(3*6)+5/(8*9)= 1
7/(4*2)+1/(3*6)+5/(8*9)= 1
7/(2*4)+1/(6*3)+5/(8*9)= 1
7/(4*2)+1/(6*3)+5/(8*9)= 1
7/(2*4)+5/(8*9)+1/(3*6)= 1
7/(4*2)+5/(8*9)+1/(3*6)= 1
7/(2*4)+5/(8*9)+1/(6*3)= 1
7/(4*2)+5/(8*9)+1/(6*3)= 1
1/(3*6)+5/(8*9)+7/(2*4)= 1
1/(3*6)+5/(8*9)+7/(4*2)= 1
1/(6*3)+5/(8*9)+7/(2*4)= 1
1/(6*3)+5/(8*9)+7/(4*2)= 1
5/(8*9)+1/(3*6)+7/(2*4)= 1
5/(8*9)+1/(3*6)+7/(4*2)= 1
5/(8*9)+1/(6*3)+7/(2*4)= 1
5/(8*9)+1/(6*3)+7/(4*2)= 1
5/(8*9)+7/(2*4)+1/(3*6)= 1
5/(8*9)+7/(4*2)+1/(3*6)= 1
5/(8*9)+7/(2*4)+1/(6*3)= 1
5/(8*9)+7/(4*2)+1/(6*3)= 1
1/(3*6)+7/(2*4)+5/(9*8)= 1
1/(3*6)+7/(4*2)+5/(9*8)= 1
1/(6*3)+7/(2*4)+5/(9*8)= 1
1/(6*3)+7/(4*2)+5/(9*8)= 1
7/(2*4)+1/(3*6)+5/(9*8)= 1
7/(4*2)+1/(3*6)+5/(9*8)= 1
7/(2*4)+1/(6*3)+5/(9*8)= 1
7/(4*2)+1/(6*3)+5/(9*8)= 1
7/(2*4)+5/(9*8)+1/(3*6)= 1
7/(4*2)+5/(9*8)+1/(3*6)= 1
7/(2*4)+5/(9*8)+1/(6*3)= 1
7/(4*2)+5/(9*8)+1/(6*3)= 1
1/(3*6)+5/(9*8)+7/(2*4)= 1
1/(3*6)+5/(9*8)+7/(4*2)= 1
1/(6*3)+5/(9*8)+7/(2*4)= 1
1/(6*3)+5/(9*8)+7/(4*2)= 1
5/(9*8)+1/(3*6)+7/(2*4)= 1
5/(9*8)+1/(3*6)+7/(4*2)= 1
5/(9*8)+1/(6*3)+7/(2*4)= 1
5/(9*8)+1/(6*3)+7/(4*2)= 1
5/(9*8)+7/(2*4)+1/(3*6)= 1
5/(9*8)+7/(4*2)+1/(3*6)= 1
5/(9*8)+7/(2*4)+1/(6*3)= 1
5/(9*8)+7/(4*2)+1/(6*3)= 1

答题的那个是“高手”!~~

不是吧!!! 这么多。
够犀利,够牛B啊

1/(3*6)+7/(2*4)+5/(8*9)= 1
1/(3*6)+7/(4*2)+5/(8*9)= 1
1/(6*3)+7/(2*4)+5/(8*9)= 1
1/(6*3)+7/(4*2)+5/(8*9)= 1
7/(2*4)+1/(3*6)+5/(8*9)= 1
7/(4*2)+1/(3*6)+5/(8*9)= 1
7/(2*4)+1/(6*3...

全部展开

1/(3*6)+7/(2*4)+5/(8*9)= 1
1/(3*6)+7/(4*2)+5/(8*9)= 1
1/(6*3)+7/(2*4)+5/(8*9)= 1
1/(6*3)+7/(4*2)+5/(8*9)= 1
7/(2*4)+1/(3*6)+5/(8*9)= 1
7/(4*2)+1/(3*6)+5/(8*9)= 1
7/(2*4)+1/(6*3)+5/(8*9)= 1
7/(4*2)+1/(6*3)+5/(8*9)= 1
7/(2*4)+5/(8*9)+1/(3*6)= 1
7/(4*2)+5/(8*9)+1/(3*6)= 1
7/(2*4)+5/(8*9)+1/(6*3)= 1
7/(4*2)+5/(8*9)+1/(6*3)= 1
1/(3*6)+5/(8*9)+7/(2*4)= 1
1/(3*6)+5/(8*9)+7/(4*2)= 1
1/(6*3)+5/(8*9)+7/(2*4)= 1
1/(6*3)+5/(8*9)+7/(4*2)= 1
5/(8*9)+1/(3*6)+7/(2*4)= 1
5/(8*9)+1/(3*6)+7/(4*2)= 1
5/(8*9)+1/(6*3)+7/(2*4)= 1
5/(8*9)+1/(6*3)+7/(4*2)= 1
5/(8*9)+7/(2*4)+1/(3*6)= 1
5/(8*9)+7/(4*2)+1/(3*6)= 1
5/(8*9)+7/(2*4)+1/(6*3)= 1
5/(8*9)+7/(4*2)+1/(6*3)= 1
1/(3*6)+7/(2*4)+5/(9*8)= 1
1/(3*6)+7/(4*2)+5/(9*8)= 1
1/(6*3)+7/(2*4)+5/(9*8)= 1
1/(6*3)+7/(4*2)+5/(9*8)= 1
7/(2*4)+1/(3*6)+5/(9*8)= 1
7/(4*2)+1/(3*6)+5/(9*8)= 1
7/(2*4)+1/(6*3)+5/(9*8)= 1
7/(4*2)+1/(6*3)+5/(9*8)= 1
7/(2*4)+5/(9*8)+1/(3*6)= 1
7/(4*2)+5/(9*8)+1/(3*6)= 1
7/(2*4)+5/(9*8)+1/(6*3)= 1
7/(4*2)+5/(9*8)+1/(6*3)= 1
1/(3*6)+5/(9*8)+7/(2*4)= 1
1/(3*6)+5/(9*8)+7/(4*2)= 1
1/(6*3)+5/(9*8)+7/(2*4)= 1
1/(6*3)+5/(9*8)+7/(4*2)= 1
5/(9*8)+1/(3*6)+7/(2*4)= 1
5/(9*8)+1/(3*6)+7/(4*2)= 1
5/(9*8)+1/(6*3)+7/(2*4)= 1
5/(9*8)+1/(6*3)+7/(4*2)= 1
5/(9*8)+7/(2*4)+1/(3*6)= 1
5/(9*8)+7/(4*2)+1/(3*6)= 1
5/(9*8)+7/(2*4)+1/(6*3)= 1
5/(9*8)+7/(4*2)+1/(6*3)= 1

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