若4x^2+4xy+2y^2-6y+9=0,试求(x^2+2y^2+3)(x^2+2y^2-3)-(x-2y)^2(x+2y)^2
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若4x^2+4xy+2y^2-6y+9=0,试求(x^2+2y^2+3)(x^2+2y^2-3)-(x-2y)^2(x+2y)^2
若4x^2+4xy+2y^2-6y+9=0,试求(x^2+2y^2+3)(x^2+2y^2-3)-(x-2y)^2(x+2y)^2
若4x^2+4xy+2y^2-6y+9=0,试求(x^2+2y^2+3)(x^2+2y^2-3)-(x-2y)^2(x+2y)^2
4x^2+4xy+2y^2-6y+9=0
(2x+y)²+(y-3)²=0
则:
2x+y=0
y-3=0
解得:
x=-3/2;y=3
(x^2+2y^2+3)(x^2+2y^2-3)-(x-2y)^2(x+2y)^2
=(x²+2y²)²-9-(x²-4y²)²
=(x²+2y²+x²-4y²)(x²+2y²-x²+4y²)-9
=6y²(2x²-2y²)-9
=12(x+y)(x-y)-9
=12×3/2×(-9/2)-9
=-81-9
=-90
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