若2x+y-4=0,求9^x*27^y的值谢谢各位啦
来源:学生作业帮助网 编辑:作业帮 时间:2024/11/01 09:22:14
若2x+y-4=0,求9^x*27^y的值谢谢各位啦
若2x+y-4=0,求9^x*27^y的值
谢谢各位啦
若2x+y-4=0,求9^x*27^y的值谢谢各位啦
2x+3y-4=0
2x+3y=4
9^x*27^y
=3^(2x)*3^(3y)
=3^(2x+3y)
=3^4
=81
2x+3y-4=0,
2x+3y=4
9^x*27^y
=3^(2x)*3^(3y)
=3^(2x+3y)
=3^4
有点难
若(x*x+y*y)(x*x+y*y)-4x*x*y*y=0,求代数式(x*x+5xy+y*y)/(x*x+2xy+y*y)的值
已知X.x+y.y-4x+2y+5=0,求4X.X-12X Y+9Y.y的值
若/X+Y-9/+(2X-Y+3)=0求X与Y的值
已知x*x-4xy+4y*y=0 求[2x(x+y)-y(x+y)]/(4x*x-4xy+y*y)的值?
若x y满足x^2+y^2-2x+4y=0求x-2y的最大值
若实数x,y满足x²+y²-2x+4y=0,求x-y的最大值
RT,若(√2x-y)+y^2+4y+4=0,求[(x-y)^2+(x+y)(x-y)]÷2x的值
已知x,y满足{3x-y=9 {x-3y=0 求x+2y+ 4y的平方/x-2y -4x的平方y/x的平方-4y的平方
若3^x=4,3^y=6,求9^2x-y+27^x-y的值.
若2x-y=0,求代数式[(x^2+y^2)-(x-y)^2+2y×(x-y)]÷4y的值
若x,y为正整数,且x^2+y^2-4y-96=0,求x、y的值
若x^2-4x+y^2-10y+29=0,求x^2y^2+2x^3y^2+x^4y^2的值
若x*x+4*y*y+2*x-4*y+2=0,求5*x*x+16*y*y的算术平方跟
若实数x、y满足x*x+y*y-2x+4y+5=0,求x-y的值
若(x+y)(x+y-1)-2=0,求x+y的值求
若3x^2+xy-2y^2=0,求(x+y/x-y+4xy/y^2-x^2)除以(x^2+2xy-3y^2/x^2-9y^2)的值
若x^2-4x+4+y^2-2/3y+2/9=0求x+1/y及x^2+1/y^2的值
若|x+y-1|+(x-y-2)²=0,求代数式(x+2y)(x-2y)-(2x-y)(-y-2x)的值.