【(x+2y)(x-2y)-(x+4y)^2】÷4y,其中x=5,y=2.(先化简,再求值,
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【(x+2y)(x-2y)-(x+4y)^2】÷4y,其中x=5,y=2.(先化简,再求值,
【(x+2y)(x-2y)-(x+4y)^2】÷4y,其中x=5,y=2.(先化简,再求值,
【(x+2y)(x-2y)-(x+4y)^2】÷4y,其中x=5,y=2.(先化简,再求值,
【(x+2y)(x-2y)-(x+4y)^2】÷4y
=[x^2﹣4y^2﹣(x+4y)^]÷4y
=(x^2﹣4y^2﹣x^2﹣8xy﹣16y^2)÷4y
=(-20y^2-8xy)÷4y
=-5y-2x
当x=5,y=2时
原式=-10-10=-20
你好,根据题意,【(x+2y)(x-2y)-(x+4y)^2】÷4y,其中x=5,y=2。解答如下——
因为: [(x+2y)(x-2y)]-(x+4y)^2/4y,其中x=-5 y=2,
所以:原题= (x^2-4y^2-x^2-8xy+16y^2)/4y
= (12y^2-8xy)/4y=4y (3y-2x)/4y
=...
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你好,根据题意,【(x+2y)(x-2y)-(x+4y)^2】÷4y,其中x=5,y=2。解答如下——
因为: [(x+2y)(x-2y)]-(x+4y)^2/4y,其中x=-5 y=2,
所以:原题= (x^2-4y^2-x^2-8xy+16y^2)/4y
= (12y^2-8xy)/4y=4y (3y-2x)/4y
=3y-2x=3*2-2*(-5)
=16
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