y=x^2/x-1,x∈[2,3]求最值
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y=x^2/x-1,x∈[2,3]求最值
y=x^2/x-1,x∈[2,3]求最值
y=x^2/x-1,x∈[2,3]求最值
^是乘号?
y=x^2/x-1,x∈[2,3]
y‘=2x/(x-1)-x^2/(x-1)^2=(2x^2-2x-x^2)/(x-1)^2=(x^2-2x)/(x-1)^2=0,x1=0,x2=2,
在x∈[2,3]内函数为单增区间,所以f(2)=4是最小值,f(3)=4.5是最大值。
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