函数f(x)=sin(2x-π/4)-2√2（sin^2x）的最小正周期是?

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函数f(x)=sin(2x-π/4)-2√2（sin^2x）的最小正周期是?
函数f(x)=sin(2x-π/4)-2√2（sin^2x）的最小正周期是?

函数f(x)=sin(2x-π/4)-2√2（sin^2x）的最小正周期是?
f(x)=sin2xcosπ/4-cos2xsinπ/4-2√2(1-cos2x)/2
=√2/2*sin2x-√2/2*cos2x+√2cos2x-√2
=√2/2*sin2x+√2/2*cos2x-√2
=sin2xcosπ/4+cos2xsinπ/4-√2
=sin(2x+π/4)-√2
T=2π/2=π

f(x)=sin2xcosπ/4-cos2xsinπ/4-2√2(1-cos2x)/2
=√2/2*sin2x-√2/2*cos2x+√2cos2x-√2
=√2/2*sin2x+√2/2*cos2x-√2
=sin2xcosπ/4+cos2xsinπ/4-√2
=sin(2x+π/4)-√2
T=2π/2=π
应是这样

函数f(x)=2sin(x+π/4)sin(x-π/4)+sin2x的值域 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f x=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 已知函数F(X)=SIN(2X+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+φ)(-π 设函数f(x)=sin(2x+ φ)(-π 设函数f(x)=sin(2x+φ)(-π 函数f(x)=sin(2x+a) -π 设函数f(x)=sin(2x+ φ)(-π 函数f(x)=sin(2x+&）(-π 函数f(x)=sin(2x+t) (-π 函数f(x)=sin(2x+a）(-π