X²+xy²-x²-y²-3xy+2x+2y-1分解因式

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X²+xy²-x²-y²-3xy+2x+2y-1分解因式
X²+xy²-x²-y²-3xy+2x+2y-1分解因式

X²+xy²-x²-y²-3xy+2x+2y-1分解因式
题目出错了么?
是不是 x²y+xy²-x²-y²-3xy+2x+2y-1?
x²y+xy²-x²-y²-3xy+2x+2y-1
=(x²y+xy²-xy)-(x²+y²+2xy-2x-2y+1
=xy(x+y-1)-[(x+y)²-2(x+y)+1]
=xy(x+y-1)-(x+y-1)²
=(x+y+1)(xy-x-y+1)
=(x+y+1)[(xy-x)-(y-1)]
=(x+y+1)[x(y-1)-(y-1)]
=(x+y+1)(x-1)(y-1)
不好意思,看到题目太晚了,

0.5x²+xy+0.5y² 因式分解：x²-xy-12y² 4x²y-xy² -9x²-y²+6xy x²-2xy+y²-9 若x²+xy-2y²=0,则x²+3xy+y²/x²+y² x²+xy-2y²=0则x²+3xy+y²/x²+y² 计算x²-x/x²×x/1-x和x²-4y²/x²+2xy+y²÷x+2y/x²+xy 因式分解 x²-2xy+y²-z² 6xy²-9x²y-y²因式分解 x²-4y²/x²+2xy+y²÷x+2y/2x²+2xy 计算：4xy²-3x²y-{3x²y-[2xy²-4x²y+2(x²y-2xy²)]急 （x²+y²)²-x²y²=(x²+y²)²-(xy)²=(x²+y²+xy)(x²+y²-xy)=(x+y)²(x-y)²-xy+xy=(x+y)²(x-y)² x²-y²+6x+9分之x²+y²-9-2xy x²y²-x²y-xy²+x+y-1因式分解 已知x²y²+x²+y²=10xy-16 求x,y （xy-x²）÷[（x²-2xy+y²）÷xy]*[(x-y)÷x²] 3x²-y²=8x²＋xy＋y²=4