若sin(π/6-α)=1/3 则cos(2π/3+2α)等于多少
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若sin(π/6-α)=1/3 则cos(2π/3+2α)等于多少
若sin(π/6-α)=1/3 则cos(2π/3+2α)等于多少
若sin(π/6-α)=1/3 则cos(2π/3+2α)等于多少
答案:-7/9
cos(2π/3+2α)=-cos(π-2π/3-2α)
=-cos(π/3-2α)
=-[1-2sin(π/6-α)^2]
=-7/9
7/9
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