数列an中,若a1=-1,a(n+1)*an=a(n+1)-an,求an

数列an中,若a1=-1,a(n+1)*an=a(n+1)-an,求an
数列an中,若a1=-1,a(n+1)*an=a(n+1)-an,求an

数列an中,若a1=-1,a(n+1)*an=a(n+1)-an,求an
a(n+1)*an=a(n+1)-an可变形为1/an+1-1/an=-1而1/a1=-1
这说明{1/an}是以-1为首项,-1为公差的等差数列,
1/an=-n
an=-1/n