(X+3)(2X-5)-(2X+1)(X-8)=41的解是?

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(X+3)(2X-5)-(2X+1)(X-8)=41的解是?
(X+3)(2X-5)-(2X+1)(X-8)=41的解是?

(X+3)(2X-5)-(2X+1)(X-8)=41的解是?
2x^2+x-15-2x^2+15x+8=41
16x=48
x=3

2x2-5x+6x-15-(2x2-16x+x-8)=41,
2x2-5x+6x-15-2x2+16x-x+8=41,
16x-7=41,
16x=48,
x=3.(x-1)(x的二次方-4+3)-x(x的二次方-5x+2)=?(x-1)(x^2-4x+3)-x(x^2-5x+2) =x(x^2-4x+3)-(x^2-4x+3)-x(x^2-5x+2) =x(x...

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2x2-5x+6x-15-(2x2-16x+x-8)=41,
2x2-5x+6x-15-2x2+16x-x+8=41,
16x-7=41,
16x=48,
x=3.

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