f(x)=2sin(2x+π/6) x属于[π/12,π/2] 求值域

f(x)=sin(2x+π/6)怎么求导 已知F(X)=根号3COS^2 X+SIN XCOS X-2SIN X*SIN(X-π/6),求F(X)的最大值 若f(x)=sin πx/6,则f(1)+f(2)+...+f(102)=? 函数f(x)=sin(2x+π/6),g(x)=cos(x+φ),|φ| f(x)=(6sin^4x-7sin^2x+2)/(sin^2x-cos^2x) 已知函数f（x）=［2sin（x-π/6）+√3sin x］cos x+sin^2x,x∈R f(sin^2x)=x/sinx 求f(x) 已知函数f(x)=sin(2x+π/6)+sin（2x+π/6）+2cos²x f(x)=sin(x+π/4)图像怎样变成F(x)=cos(2x) f(x)为奇函数,x>0,f(x)=sin 2x+cos x,则x f(x)=sin^2-sin[2x-(π/6)]的值域过程 f(x)=sin(x-π）cos（π+x）+sin（x+π/2）cos(-x) ①f(x)最小正周期 ②[-π/6,π/2]f(x)最大值和最小值③f(x)递增区间 f(x)=（1+cotx)sin^2x-2sin(x+π/4)sin(x-π/4)还有一题, 已知函数f(x)=(1+1 anx)sin^2x+m sin(x+π/4)sin(x-π/4) 为什么 f(x)=sin(x+π/2)=cosx f(x)=2根号3sin^2x-sin(2x-π/3)若x属【-π/2,0】,求函数f（x）的最大值 设函数 f(x)=sin(2x+y),(-π 设函数f(x)=sin(2x+φ)(-π