作业帮2^log4(2-√3) + 3^log9(2+√3)的值是多少啊?
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2^log4(2-√3) + 3^log9(2+√3)的值是多少啊?
2^log4(2-√3) + 3^log9(2+√3)的值是多少啊?
2^log4(2-√3) + 3^log9(2+√3)的值是多少啊?
2^log4(2-√3) + 3^log9(2+√3)
＝(2-√3)^log4(2) + (2+√3)^log9(3)
＝(2-√3)^(1/2) + (2+√3)^(1/2)
＝√6
公式:a^logb(c)=c^logb(a)
如题{log(2√2) - 3log√3 - 3} / {log9 - log4 + 4}
(log2 5+log4 125)log3 2/ log根号3 5
(log2(5)+log4(125))(log3(2)/log√3(5))怎么解?
求值:-log2log2√√√2 ,log4 (8)-log1/9 (3)-log√2 (4) ; (log4(3))*（log9(25))*(log5(8))
log4 (x+3)+log(1/4) (x-3)=log(1/4) (x-1)+log4 (2x+1)的解集,
2^log4(3)
log4(3x-2)
2^log4^3=?
数学对数函数 (6 16:21:23)log½3＋log2 3+log4 1／9+log√2 √3,求值
计算：2^log4(2--根号3）^2+2^log(2+根号3）^2
[log3（4）+log根下3（2）][log2(9)+log4(根3)]
(log2(5）+log4（125））×log3（2）/log根号3（5）
(log2^5+log4^125)(log3^2)/(log(根号3)^5 要具体的过程,
log4^(13-3x)*log(x-1)^2=1的解
log4 8-log1/9 3=log 根号2 1/4怎么算
log (log2)^2 - (log4)(log20) + (log20)^2
计算：2^[log4(3) -2]
log25^2/1*log4^5-log1/3^3-log2^4+5^log根号5^2要过程,答案为11分之4log25^2/1*log4^5-log1/3^3-log2^4+5^log根号5^2过程啊,