设集合A=｛y| y= x^2-4x+3,x∈R｝,集合B={m|m=-n^2-2n,n∈R｝,求A∩B,A∪B

设集合A=｛y| y= x^2-4x+3,x∈R｝,集合B={m|m=-n^2-2n,n∈R｝,求A∩B,A∪B
设集合A=｛y| y= x^2-4x+3,x∈R｝,集合B={m|m=-n^2-2n,n∈R｝,求A∩B,A∪B

设集合A=｛y| y= x^2-4x+3,x∈R｝,集合B={m|m=-n^2-2n,n∈R｝,求A∩B,A∪B
y=x^2-4x+3=(x-2)^2-1>=-1
所以A是大于等于-1的实数的集合
m=-n^2-2n=-(n+1)+1