(x-2)²分之x=x-2分之a+(x-2)²分之b(a,b为常数)则a= ,b=

(x-2)²分之x=x-2分之a+(x-2)²分之b(a,b为常数)则a= ,b=
(x-2)²分之x=x-2分之a+(x-2)²分之b(a,b为常数)则a= ,b=

(x-2)²分之x=x-2分之a+(x-2)²分之b(a,b为常数)则a= ,b=
【参考答案】

x/(x-2)²=[a/(x-2)]+[b/(x-2)²]
x/(x-2)²=[a(x-2)/(x-2)²]+[b/(x-2)²]
x/(x-2)²=[a(x-2)+b]/(x-2)²
x=a(x-2)+b
x=ax-2a+b
∴ a=1, -2a+b=0
∴a=1, b=2