已知x^-y^=8,x-y=4,求x+y的值.
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已知x^-y^=8,x-y=4,求x+y的值.
已知x^-y^=8,x-y=4,求x+y的值.
已知x^-y^=8,x-y=4,求x+y的值.
∵x^2-y^2=(x+y)(x-y)=8
(x-y)=4
∴(x+y)=2
∵x^2-y^2=(x+y)×(x-y)=8
又(x-y)=4
∴(x+y)=2
两式相除,等于2
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