{2x+y=74x+5y=11
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{2x+y=74x+5y=11
{2x+y=7
4x+5y=11
{2x+y=74x+5y=11
这应该不是高中的数学题吧,这是初中的二元一次方程组.
{2x+y=7 (1)
4x+5y=11(2)
将(1)乘以2得到:4x+2y=14(3)
将(3)减去(2)得-3y=3 故y=-1
再把y=-1带入(1)中得到x=4
所以原方程组的解为:{x=4
y=-1
将2x+y=7乘2得 4x+2y=14
4x+2y-(4x+5y)=3
-3y=3
y=-1
x=4
(方程)1*2=>4X+2Y=14 ;
1(方程)-2(方程)=>-3y=3
y=-1;
y=-1带入方程1得
x=4;
{y=-1
x=4
2x+y=7
y=7-2*x
4x+5y=11
4x+5(7-2x)=11
x=4
y=-1
∵2x+y=7
∴.......①
把①代入4x+5y=11
得4x+5(7-2x)=11
x=4
∵y=7-2x
∴y=-1
x=4,y=-1.
4(x-y)-3(x-y)=9 5(x-y)+2(x-y)=11
3(x+y)-4(x-y)=11,2(x-y)+5(x+y)=27
{2x+y=74x+5y=11
x-y/x-x+y/y-(x+y)(x-y)/y² y/x=2
已知x-y/x+y=3,求代数式5(x-y)/x+y-x+y/2(x-y)
2(x-y)=5y,x-y=-5
3(x+y)-2(x-y)=11 4(x+y)+3(x-y)=9
x+2y=5x-6y=11
3*X=Y X/2=Y/5+11
x-y / 5y= (y-x)^2 / ( )
x*x+2x+y*y-4y+5=0 x= y=
x+y/2+x-y/6=5 2(x+y)-3(x-y)=-2
解方程组(x+y)(x-2y)=-5 (x-y)(x+2y)=7
3(x+y)+2(x-y)=36 4(x+y)-5(x-y)=2
{6(x-y)-7(x+y)=21 {2(x-y)-5(x+y)=-1
6(x-y)-2(x+y)=14 3(x-y)+(x+y)=5
求(X+Y)(X-Y)(X²+Y²),X=5 Y=2,
(x-y)/(x+y)=3求( 3x-2y-1)/(x+y-5)