log9 16×log32 81=
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log9 16×log32 81=
log9 16×log32 81=
log9 16×log32 81=
log9 16×log32 81
= (lg16 / lg9) × (lg81 / lg32)
= 4lg2 / (2lg3) × 4lg3 / (5lg2)
= 8/5
log9 16×log32 81=
log9^16乘以log32^81=?
谁会这几道log的数学题log4 16 ×log9 8=?3^(2+log32)=?5^(2-log5 3)=?
log9 81=?
9^(log32)=
计算:log9(16)×log8(81)
log9(16) ×log2(27)=6步骤
log34=2log32为什么
log9 3+log9 27=怎么求~
log9^27=
请问谁知道 log9(16)*log8(81)咋解?
为什么log9 (9/2)=log3(81/4)
设log32=log23x,则x=?
设log32=log23x,则x=?
设log32=a则log29等于
log5[log2(log9/log3)]=?
log3*2/log9*4=?
若log32=log23的x次方,则x等于?