(a+1/a方-a+4/1-a方)/a方+2a-3/a+3

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(a+1/a方-a+4/1-a方)/a方+2a-3/a+3
(a+1/a方-a+4/1-a方)/a方+2a-3/a+3

(a+1/a方-a+4/1-a方)/a方+2a-3/a+3
题是这样的吧:
[(a+1)/(a²-a)-(a+4)/(1-a²)]÷(a²+2a-3)/(a+3)
原式= [(a+1)/a(a-1)+(a+4)/(a+1)(a-1)]×(a+3)/(a+3)(a-1)
=[(a²+2a+1)/a(a+1)(a-1)+(a²+4a)/a(a+1)(a-1)]×1/(a-1)
=[(2a²+6a+1)/a(a+1)(a-1)]×1/(a-1)
=(2a²+6a+1)/a(a+1)(a-1)²

=[(a+1)/a(a-1)+4/(1+a)(1-a)]/a^2+(2a-3)/(a+3)=[(a+1)^2-4a]/a^3(a+1)(a-1)+(2a-3)/(a+3)=(a-1)^2/a^3(a+1)(a-1)+(2a-3)/(a+3)=(a-1)/a^3(a+1)+(2a-3)/(a+3)=(2a^5-a^4-3a^3+a^2+2a-3)/a^3(a+1)(a+3)